No, it isn't. You think so because of the resulting black hole being somehow magically a space vacuum-kind of thing? That's not how black holes work. If that star implodes into a black hole, it leaves a celestial body with (more or less) the same gravitational pull as the star had before. Outside of not emitting light, it's functionally identical to the sun it descends from in every relevant way.UltimateSpinDash wrote: ↑Sun Jun 28, 2020 11:41 amI mean, yeah, you can prevent Romulus from being blown up by a Nova if you destroy the sun with a black hole instead, but Romulus is still screwed afterwards.
Conversly, if your concern is the resulting lack of emitted energy, then that is no concern either. Romulus isn't circling that star-gone-black-hole, so it's reasonable to assume that the preceeding star had little to no effect on the level of energy going to Romulus. It won't suddenly be night, when there was day. At best, the Romulan sky will be missing a particularly bright star at night. Ok, it might have, depending on size and relative position, one less object that is similar in terms of levels of light as our moon, but that object wouldn't be that big all the time in the first place, given how far the star would be for considerable lengths of time anyways, due to the orbital mechanics and distances involved in binary star systems. At best, some species would get their life- or reproductive-cycle screwed up, similar to how some species on this planet have such cycles corresponding with our moon. An ecological disaster at "best", but not world-ending.
This leaves the initial explosion of the star going supernova and yes, a regular star that goes nova releases enough energy to still essentially evaporate the Earth's atmosphere within a circle of roughly 25 lightyears (though it would still take roughly 25 years for the energy to travel the distance). However, we know that Hobus is not a regular supernova-going star. It is much much smaller than it would need to, so it is likely that it doesn't emit enough energy to do that (in fact I'd argue, to reach the levels of energy needed to collapse a small star into a black hole, you'd need almost all the energy the star can release in an explosion to be "aimed", if not outright directed inwards, lessening the amount of energy that the star can emit in it's collapse in the first place and indicating artificial means by the by). Now it's up to debate how big Hobus and how far away it was from Romulus in the first place, but I'd argue that since it is never made a mention of Romulus being a binary system or that Romulus has literally two suns (and not just one sun and a really bright star on it's firmament), that Hobus is so far way to be functionally irrelevant for Romulus in every coneivable way (in stellar or orbital terms) and, in the case it implodes, the energies released outwards are limited by necessity and could be dampened if not completely negated by the planetary shields of Romulus.
The reason I think this may very well be the case are, several episodes of Star Trek showing ships being well within the range of stars going supernova and not enduring much damage or any damage at all even. In TNG's Tin Man, the Enterprise gets thrown into a distance of 3.8 billion kilometers from within a star stated to be going supernova and endures absolutely no damage by the explosive implosion. That is just above 0.0004 lightyears. In Voyager's "The Q and the Grey", it is mentioned that Voyager is the closest Starfleet vessel ever to osberve and endure a star going supernova, making a vague reference to "several billion kilometers". Let's assume it was just above 1 billion kilometer, which is still just above 0.0001 lightyears. I find it reasonable to argue, that Hobus must be a lot further away from the Romulus' system primary star than that and planetary shields are, obviously, much stronger than anything a starship can field.